Further Mathematics Questions and Answers
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
Express (14N, 240°) as a column vector.
\(\begin{pmatrix} -7 \\ -7\sqrt{3} \end{pmatrix}\)
\(\begin{pmatrix} 7\sqrt{3} \\ 7\sqrt{3} \end{pmatrix}\)
\(\begin{pmatrix} -7\sqrt{3} \\ -7 \end{pmatrix}\)
\(\begin{pmatrix} 7 \\ -7\sqrt{3} \end{pmatrix}\)
Correct answer is A
\(F = \begin{pmatrix} F_{x} \\ F_{y} \end{pmatrix} = \begin{pmatrix} F\cos \theta \\ F\sin \theta \end{pmatrix}\)
\((14N, 240°) = \begin{pmatrix} 14\cos 240 \\ 14\sin 240 \end{pmatrix}\)
= \(\begin{pmatrix} 14 \times -0.5 \\ 14 \times \frac{-\sqrt{3}}{2} \end{pmatrix}\)
= \(\begin{pmatrix} -7 \\ -7\sqrt{3} \end{pmatrix}\)
Evaluate \(\frac{\tan 120° + \tan 30°}{\tan 120° - \tan 60°}\)
\(\sqrt{3} + \sqrt{2}\)
\(\frac{2}{3}\)
\(\frac{1}{3}\)
\(-2\sqrt{3}\)
Correct answer is C
No explanation has been provided for this answer.
Find \(\lim\limits_{x \to 3} (\frac{x^{3} + x^{2} - 12x}{x^{2} - 9})\)
\(\frac{7}{2}\)
\(0\)
\(\frac{-7}{2}\)
\(-7\)
Correct answer is A
\(\lim\limits_{x \to 3} (\frac{x^{3} + x^{2} - 12x}{x^{2} - 9}) = \lim\limits_{x \to 3} (\frac{x^{3} - 3x^{2} + 4x^{2} - 12x}{(x - 3)(x + 3)}\)
\(\lim\limits_{x \to 3} (\frac{(x^{2} + 4x)(x - 3)}{(x - 3)(x + 3)} = \lim\limits_{x \to 3} (\frac{x^{2} + 4x}{x + 3})\)
=\(\frac{3^{2} + 4(3)}{3 + 3} = \frac{21}{6} = \frac{7}{2}\)
Find the distance between the points (2, 5) and (5, 9).
4 units
5 units
12 units
14 units
Correct answer is B
Distance between two points (a, b) and (c, d) = \(\sqrt{(d - b)^{2} + (c - a)^{2}}
Distance between (2, 5) and (5, 9) = \(\sqrt{(9-5)^{2} + (5-2)^{2}}\)
= \(\sqrt{16 + 9} = \sqrt{25} = 5 units\)
15.25m
13.25m
11.25m
10.25m
Correct answer is C
Maximum height (H) = \(\frac{u^{2}}{2g}\)
= \(\frac{15^{2}}{2 \times 10} = \frac{225}{20}\)
= \(11.25m\)