Further Mathematics Questions and Answers

\(T_{n} = a + (n - 1)d\)

\(380 = 9 + (n - 1)7\)

\(380 = 9 + 7n - 7 \implies 380 = 2 + 7n\)

\(7n = 380 - 2 = 378 \therefore n = \frac{378}{7} = 54\)

The equation of a circle with centre coordinate (a, b) and radius r is :

\((x - a)^{2} + (y - b)^{2} = r^{2}\)

Given centre = (2, -3) and radius r = 2 units

Equation = \((x - 2)^{2} + (y - (-3))^{2} = 2^{2}\)

\(x^{2} - 4x + 4 + y^{2} + 6y + 9 = 4\)

\(x^{2} + y^{2} - 4x + 6y + 4 + 9 - 4 = 0 \implies x^{2} + y^{2} - 4x + 6y + 9 = 0\)

The sum of deviations from the mean of a set of numbers equals 0.

\((k+3)^{2} + (k+7) + (-2) + k + (k+2)^{2} = 0\)

\((k^2 + 6k + 9) + (k+7) - 2 + k + (k^2 + 4k + 4) = 0\)

\(2k^{2} + 12k + 18 = 0\)

\(2k^{2} + 6k + 6k + 18 = 2k(k + 3) + 6(k + 3) = 0\)

\(k = -3 (twice)\)

\(F = F\cos\theta + F\sin\theta\)

\(\implies 90N = 90\cos 120° + 90\sin 120°\)

\(120N = 120 \cos 240° + 120 \sin 240°\)

\(R = F_{1} + F_{2} \)

= \((90 \cos 120 + 120 \cos 240)i + (90\sin 120 + 120 \sin 240)j\)

= \(90(-0.5) + 120(-0.5))i + (90(\frac{\sqrt{3}}{2}) + (120(-\frac{\sqrt{3}}{2}))j\)

= \(-105i - 15\sqrt{3}j = -15(7i + \sqrt{3}j)\)

P(at least one head) = 1 - P(4 tails)

Let \(p = \frac{1}{2}\) = probability of head and \(q = \frac{1}{2}\) = probability of tail.

\((p + q)^{4} = p^{4} + 4p^{3}q + 6p^{2}q^{2} + 4pq^{3} + q^{4}\)

P(4 tails) = \(q^{4} = (\frac{1}{2})^{4} = \frac{1}{16}\)

P(at least one head) = \(1 - \frac{1}{16} = \frac{15}{16}\)