Further Mathematics Questions and Answers
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
Express log18+log12 in terms of log2
3 log 2
4 log 2
-3 log 2
-4 log 2
Correct answer is D
log18+log12=log8−1+log2−1
= log2−3+log2−1
= −3log2−1log2=−4log2
Given that a56×a−1n=1, solve for n
-6.00
-1.20
0.83
1.20
Correct answer is D
a56×a−1n=1
⟹a56+−1n=a0
Equating bases, we have
56−1n=0
5n−66n=0
5n−6=0⟹5n=6
n=65=1.20
200°
90°
60°
0°
Correct answer is D
sinθ=tanθ⟹sinθ1=sinθcosθ
Equating, we have
cosθ=1⟹θ=cos−11
= 0°
\frac{-x}{1 - x}, x \neq 1
\frac{1}{1 - x}, x \neq 1
\frac{-1}{1 - x}, x \neq 1
\frac{x}{1 - x}, x \neq 1
Correct answer is A
x * y = x + y - xy
Let x^{-1} be the inverse of x, so that
x * x^{-1} = x + x^{-1} - x(x^{-1}) = 0
x + x^{-1} - x(x^{-1}) = 0 \implies x(x^{-1}) - x^{-1} = x
x^{-1}(x - 1) = x \implies x^{-1} = \frac{x}{x - 1}
= \frac{x}{-(1 - x)} = \frac{-x}{1 - x}, x \neq 1
Express (14N, 240°) as a column vector.
\begin{pmatrix} -7 \\ -7\sqrt{3} \end{pmatrix}
\begin{pmatrix} 7\sqrt{3} \\ 7\sqrt{3} \end{pmatrix}
\begin{pmatrix} -7\sqrt{3} \\ -7 \end{pmatrix}
\begin{pmatrix} 7 \\ -7\sqrt{3} \end{pmatrix}
Correct answer is A
F = \begin{pmatrix} F_{x} \\ F_{y} \end{pmatrix} = \begin{pmatrix} F\cos \theta \\ F\sin \theta \end{pmatrix}
(14N, 240°) = \begin{pmatrix} 14\cos 240 \\ 14\sin 240 \end{pmatrix}
= \begin{pmatrix} 14 \times -0.5 \\ 14 \times \frac{-\sqrt{3}}{2} \end{pmatrix}
= \begin{pmatrix} -7 \\ -7\sqrt{3} \end{pmatrix}