Find the distance between the points (2, 5) and (5, 9).
Find the distance between the points (2, 5) and (5, 9).
4 units
5 units
12 units
14 units
Correct answer is B
Distance between two points (a, b) and (c, d) = \(\sqrt{(d - b)^{2} + (c - a)^{2}}
Distance between (2, 5) and (5, 9) = \(\sqrt{(9-5)^{2} + (5-2)^{2}}\)
= \(\sqrt{16 + 9} = \sqrt{25} = 5 units\)
P, Q, R, S are points in a plane such that PQ = 8i - 5j, QR = 5i + 7j, RS = 7i + 3j and PS = x...
If \(f(x) = 2x^{2} - 3x - 1\), find the value of x for which f(x) is minimum....
Given that \(a^{\frac{5}{6}} \times a^{\frac{-1}{n}} = 1\), solve for n...
Given that P = {x : 2 ≤ x ≤ 8} and Q = {x : 4 < x ≤ 12} are subsets of the universal set...