A ball is thrown vertically upwards with a velocity of 15\(ms^{-1}\). Calculate the maximum height reached. \([g = 10ms^{-2}]\)

A.

15.25m

B.

13.25m

C.

11.25m

D.

10.25m

View answer & explanation

Correct answer is C

Maximum height (H) = \(\frac{u^{2}}{2g}\)

= \(\frac{15^{2}}{2 \times 10} = \frac{225}{20}\)

= \(11.25m\)

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