Further Mathematics questions and answers

Further Mathematics Questions and Answers

Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.

416.

The probability that Kofi and Ama hit a target in a shooting competition are \(\frac{1}{6}\) and \(\frac{1}{9}\) respectively. What is the probability that only one of them hit the target?

A.

\(\frac{1}{54}\)

B.

\(\frac{13}{54}\)

C.

\(\frac{20}{27}\)

D.

\(\frac{41}{54}\)

Correct answer is B

P(only one hit target) = P(Kofi not Ama) + P(Ama not Kofi)

P(Kofi not Ama) = P(Kofi and Ama') = \(\frac{1}{6} \times \frac{8}{9} = \frac{8}{54}\)

P(Ama not Kofi) = P(Ama and Kofi') = \(\frac{1}{9} \times \frac{5}{6} = \frac{5}{54}\)

P(only one hit target) = \(\frac{8}{54} + \frac{5}{54} = \frac{13}{54}\)

417.

The mean of 2, 5, (x + 2), 7 and 9 is 6. Find the median.

A.

5.5

B.

6.0

C.

6.5

D.

7.0

Correct answer is D

\(\frac{2 + 5+ (x + 2) + 7 + 9}{5} = 6 \implies 25 + x = 30\)

\(x = 5 \therefore x + 2 = 5 + 2 = 7\)

Arranging the numbers in ascending order: 2, 5, 7, 7, 9. 

Median = 7.0

418.

Determine the coefficient of \(x^{2}\) in the expansion of \((a + 3x)^{6}\)

A.

\(18a^{2}\)

B.

\(45a^{4}\)

C.

\(135a^{4}\)

D.

\(1215a^{2}\)

Correct answer is C

\((a + 3x)^{6}\).

The coefficient of \(x^{2}\) is:

\(^{6}C_{4}(a)^{6 - 2} (3x)^{2} = \frac{6!}{(6 - 4)! 4!} (a^{4})(9x^{2})\)

\(15 \times a^{4} \times 9 = 135a^{4}\)

419.

Find the equation of a circle with centre (-3, -8) and radius \(4\sqrt{6}\)

A.

\(x^{2} - y^{2} - 6x + 16y + 23 = 0\)

B.

\(x^{2} + y^{2} + 6x + 16y - 23 = 0\)

C.

\(x^{2} + y^{2} + 6x - 16y + 23 = 0\)

D.

\(x^{2} + y^{2} - 6x + 16y + 23 = 0\)

Correct answer is B

Equation of a circle: \((x - a)^{2} + (y - b)^{2} = r^{2}\)

where (a, b) and r are the coordinates of the centre and radius respectively.

Given : \((a, b) = (-3, -8); r = 4\sqrt{6}\)

\((x - (-3))^{2} + (y - (-8))^{2} = (4\sqrt{6})^{2}\)

\(x^{2} + 6x + 9 + y^{2} + 16y + 64 = 96\)

\(x^{2} + y^{2} + 6x + 16y + 9 + 64 - 96 = 0\)

\(\implies x^{2} + y^{2} + 6x + 16y - 23 = 0\)

420.

Evaluate \(\frac{1}{1 - \sin 60°}\), leaving your answer in surd form.

A.

\(1 - \sqrt{3}\)

B.

\(2 - \sqrt{3}\)

C.

\(4 - 2\sqrt{3}\)

D.

\(4 + 2\sqrt{3}\)

Correct answer is D

No explanation has been provided for this answer.