Further Mathematics Questions and Answers
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
The fourth term of a geometric sequence is 2 and the sixth term is 8. Find the common ratio.
±1
±2
±3
±4
Correct answer is B
Tn=arn−1 (Exponential sequence)
T4=ar3=2....(1)
T6=ar5=8......(2)
Divide (2) by (1),
ar5ar3=82
r2=4
r=±2
5
6
7
8
Correct answer is A
(327x)(23)=(1229)
(3×2+2×37×2+x×3)=(1229)
⟹14+3x=29
3x=29−14=15
x=5
The inverse of a function is given by f−1:x→x+14.
f:x→4x−1
f:x→4x+1
f:x→4x−14
f:x→x−12
Correct answer is A
The inverse of the inverse of a function gives the function
i.e f−1(f−1(x))=f(x)
f−1(x)=x+14
Take y = x, so
f−1(y)=y+14
Let x=f−1(y),
x=y+14⟹4x=y+1
y=f(x)=4x−1
−34
−23
45
32
Correct answer is A
92x+1=813x+2
92x+1=(92)3x+2
92x+1=96x+4
Equating powers,
2x+1=6x+4⟹−3=4x
∴
A line is perpendicular to 3x - y + 11 = 0 and passes through the point (1, -5). Find its equation.
3y - x -14 = 0
3x + y + 1 = 0
3y + x + 1 = 0
3y + x + 14 = 0
Correct answer is D
3x - y + 11 = 0 \implies y = 3x + 11
Gradient = 3
Gradient of perpendicular line = \frac{-1}{3}
\therefore \frac{y - (-5)}{x - 1} = \frac{-1}{3}
3(y + 5) = 1 - x
3y + x + 15 - 1 = 3y + x + 14 = 0