Further Mathematics questions and answers

Further Mathematics Questions and Answers

Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.

401.

Find, correct to two decimal places, the acute angle between \(p = \begin{pmatrix} 13 \\ 14 \end{pmatrix}\) and \(q = \begin{pmatrix} 12 \\ 5 \end{pmatrix}\).

A.

23.52°

B.

24.50°

C.

29.52°

D.

29.82°

Correct answer is B

\(p . q = |p||q|\cos \theta\)

\(156 + 70 = (\sqrt{13^{2} + 14^{2}})(\sqrt{12^{2} + 5^{2}}) \cos \theta\)

\(226 = (\sqrt{365})(13) \cos \theta\)

\(\frac{226}{13\sqrt{365}} = \cos \theta\)

\(\cos \theta = 0.9099\)

\(\theta = 24.50°\)

402.

Find the unit vector in the direction of (-5i + 12j).

A.

\(\frac{1}{13}(-5i - 12j)\)

B.

\(\frac{1}{13}(5i - 12j)\)

C.

\(\frac{1}{13}(-5i + 12j)\)

D.

\(\frac{1}{13}(5i + 12j)\)

Correct answer is C

The unit vector \(\hat{n} = \frac{\overrightarrow{r}}{|r|}\)

\(\hat{n} = \frac{-5i + 12j}{\sqrt{(-5)^{2} + (12)^{2}} \)

= \(\frac{-5i + 12j}{13} \)

403.

The functions f and g are defined on the set, R, of real numbers by \(f : x \to x^{2} - x - 6\) and \(g : x \to x - 1\). Find \(f \circ g(3)\)

A.

-8

B.

-6

C.

-4

D.

-3

Correct answer is C

\(f : x \to x^{2} - x - 6\); \(g : x \to x - 1\)

\(g(3) = 3 - 1 = 2\)

\(f(g(3)) = f(2) = 2^{2} - 2 - 6 = 4 - 2 - 6 = -4\)

404.

Given that \(q = 9i + 6j\) and \(r = 4i - 6j\), which of the following statements is true?

A.

r and q are collinear

B.

r and q are perpendicular

C.

The magnitude of r is 52 units

D.

The projection of r on q is \(\sqrt{117}\) units.

Correct answer is B

The dot product of two perpendicular forces = 0

\((9i + 6j).(4i - 6j) = 36 - 36 = 0\)

Hence, r and q are perpendicular.

405.

A particle starts from rest and moves in a straight line such that its velocity, v, at time t seconds is given by \(v = (3t^{2} - 2t) ms^{-1}\). Determine the acceleration when t = 2 secs.

A.

\(4 ms^{-2}\)

B.

\(6 ms^{-2}\)

C.

\(8 ms^{-2}\)

D.

\(10 ms^{-2}\)

Correct answer is D

\(v(t) = (3t^{2} - 2t) ms^{-1}\)

\(a(t) = \frac{\mathrm d v}{\mathrm d t} = (6t - 2) ms^{-2}\)

\(a(2) = 6(2) - 2 = 12 - 2 = 10 ms^{-2}\)