Further Mathematics Questions and Answers
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
Simplify \(\frac{9*3^{n+1} - 3^{n+2}}{3^{n+1} - 3^{n}}\)
3
9
27
81
Correct answer is B
\(\frac{9*3^{n+1} - 3^{n+2}}{3^{n+1} - 3^{n}}\)
= \(\frac{3^n * 3^n * 3^1 * - 3^2 * 3^2}{3^n * 3^1 - 3^n}\)
= \(\frac{3^n (3^2 * 3^1)}{3^n (3^1 - 1)}\)
= \(\frac{27-9}{3-1}\)
= \(\frac{18}{2}\)
= 9
If \(log_{10}(3x+1) + log_{10}4 = log_{10}(9x+2)\), find the value of x
\(\frac{1}{3}\)
1
2
3
Correct answer is C
\(log_{10}(3x+1) + log_{10}4 = log_{10}(9x+2)\)
\(log_{10}4(3x+1) = log_{10}(9x+2)\)
4(3x+1) = 9x + 2
12x -4 = 9x + 2
12x - 9x = 2 + 4
3x = 6
x = 2
(\(\frac{3√6}{√5} + \frac{√54}{3√5}\))\(^{-1}\)
\(\frac{5√3}{6}\)
\(\frac{3√15}{6}\)
\(\frac{5√6}{12}\)
\(\frac{5√3}{12}\)
Correct answer is C
(\(\frac{3√6}{√5} + \frac{√54}{3√5}\))\(^{-1}\)
= \(\frac{√5(3√5)}{3√6 + 3√6}\)
= \(\frac{3*5}{6√6} = \frac{5}{2√6}\)
= \(\frac{5*2√6}{2√6+2√6} = \frac{10√6}{4*6}\)
= \(\frac{5√6}{12}\)
16
8
4
2
Correct answer is D
x∆y = \(\sqrt{x+y - \frac{xy}{4}}\)
4∆3 = \(\sqrt{4+3 - \frac{4*3}{4}}\)
= \(\sqrt{4+3-3}\)
= \(\sqrt{4}\)
= 2.
The table shows the distribution of marks obtained by some students in a test
| Marks | 0-9 | 10-19 | 20-29 | 30-39 | 40-49 |
| Frequency | 4 | 12 | 16 | 6 | 2 |
Find the modal class mark.
4.5
14.5
24.5
34.5
Correct answer is C
Modal class 20 - 29
Modal class mark = \(\frac{20+29}{2}\)
= \(\frac{49}{2}\)
= 24.5