Further Mathematics Questions and Answers
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
Find the equation of the normal to the curve y= 2x\(^2\) - 5x + 10 at P(1, 7)
y+x-3 =0
y-x+6=0
y - x - 6=0
y -x+ 3 =0
Correct answer is C
From y= 2x- 5x 10 ; dy/dx= 4x-5
But at (1, 7); m\(_1\) = (dy/dx)\(_{1,7}\)
= 4(1) - 5 = -1
Using m\(_1\)m\(_2\),= -1; m\(_2\) = 1.
Gradient m\(_2\), of normal at (1,7) is 1.
Using y - y\(_1\) = m(x - x\(_1\))
y - 7 = 1(x - 1) ;
y - 7 = x - 1
y - x - 6 = 0
The gradient ofy= 3x\(^2\) + 11x + 7 at P(x.y) is -1. Find the coordinates of P.
(-3, -2)
(-2,-3)
(-2,3)
(2,2)
Correct answer is B
y= 3x\(^2\) + 11x +7;
dy/dx = 6x + 11= -1;
6x = -12;
x=-2
y= 3x\(^2\) + 11x + 7
At x-2,
y= 3(-2)\(^2\) +11(-2) + 7
= 12 - 22 + 7= -3
p(x, y) = (-2,-3)
12/91
16/91
30/91
32/91
Correct answer is D
Total balls = 8+4+2= 14
n(R) = 8, n (B) =4, n(G) = 2
Without replacement, it is p(RB) or p(BR)
= (8/14 x 4/13) + (4/14 + 8/13) = 16/91 + 16/91
= 32/91
y⟺ ~x v z
y⟺ ~x v ~z
y⟺ ~x ^ ~z
y⟺ ~x ^ z
Correct answer is C
No explanation has been provided for this answer.
If 2i +pj and 4i -2j are perpendicular, find the value of p.
2
3
4
5
Correct answer is C
(2i + pi) (4i - 2j) =0
2 x 4 - p x 2=0 ;
8-2p = 0; 2p-8;
p=4