Further Mathematics questions and answers

Further Mathematics Questions and Answers

Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.

96.

If √5 cosx + √15sinx = 0, for 0° < x < 360°, find the values of x.

A.

30° and 150°

B.

150° and 210°

C.

150° and 330°

D.

210° and 330°

Correct answer is C

√5 cosx + √15sinx = 0;

√5 (cosx + √3sinx) = 0

cosx = -sinx√3;  \(\frac{sinx}{cos}\) = \(\frac{-1}{√3}\)

tanx =  \(\frac{-1}{√3}\);  x = 150° or 330°

97.

A committee consists of 6 boys and 4 girls. In how many ways can a sub-committee consisting of 3 boys and 2 girls be formed if one particular boy and one particular girl must be on the sub-committee?

A.

120

B.

80

C.

56

D.

30

Correct answer is D

The required committee can be formed in 

(a boy and a girl are already part of the committee so we need two more boys and a girl).

\(^{5}C_{2}\) * \(^{3}C_{1}\) = \(\frac{5 * 4*3*2*1}{3* 2 * 2*1}\) * \(\frac{ 3* 2* 1}{ 2 * 1}\)

10  * 3 = 30ways.

98.

The first term of an AP is 4 and the sum of the first three terms is 18. Find the product of the first three terms

A.

292

B.

272

C.

192

D.

172

Correct answer is C

Using the sum of an AP, S\(_n\) = \(\fra{n}{2}\) [ 2a + (n - 1)d]

S\(_3\) = \(\fra{3}{2}\) [ 2a + (3 - 1)d]

18 = \(\fra{3}{2}\) [ 2a + 2d]

2a + 2d = 12

a = 4

2(4) + 2d = 18 --> 8 + 2d = 12

2d = 4; d = 2

a = 4: a + d

=  4 + 2 = 6

a + 2d = 4 + 2]2] 

= 8

product of the terms = 4 * 6 * 8 = 192

99.

If sin x = \(\frac{12}{13}\) and sin y = \(\frac{4}{5}\), where x and y are acute angles, find  cos (x + y)

A.

\(\frac{48}{65}\)

B.

\(\frac{13}{15}\)

C.

\(\frac{-33}{65}\)

D.

\(\frac{-48}{65}\)

Correct answer is C

From Pythagoras' theorem

when sin x = \(\frac{12}{13}\), cos x = \(\frac{5}{13}\)

Using cos (x + y) = cosx cosy - sinxsiny

\(\frac{5}{13}\) * \(\frac{3}{5}\) - \(\frac{12}{13}\) * \(\frac{4}{5}\)

= \(\frac{-33}{65}\)

100.

If ( 1- 2x)\(^4\) = 1 + px + qx\(^2\) - 32x\(^3\) + 16\(^4\), find the value of (q - p)

A.

-32

B.

-16

C.

16

D.

32

Correct answer is D

( 1- 2x)\(^4\) = 1 + px + qx\(^2\) - 32x\(^3\) + 16\(^4\) 

compared with:  1 - 8x + 24x\(^2\) - 32x\(^3\) + 16\(^4\)

q = 24 and p = -8

(q - p) = 24 - [-8] = 32