\(\frac{1}{3}\)
1
2
3
Correct answer is C
\(log_{10}(3x+1) + log_{10}4 = log_{10}(9x+2)\)
\(log_{10}4(3x+1) = log_{10}(9x+2)\)
4(3x+1) = 9x + 2
12x -4 = 9x + 2
12x - 9x = 2 + 4
3x = 6
x = 2
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