Further Mathematics questions and answers

Further Mathematics Questions and Answers

Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.

61.

Solve: \(3^{2x-2} - 28(3^{x-2}) + 3 = 0\)

A.

x = -2 or x = 1

B.

x = 0 or x = -3

C.

x = 2 or x = 1

D.

x = 0 or x = 3

Correct answer is D

\(3^{2x-2} - 28(3^{x-2}) + 3 = 0\)

\(\frac{3^{2x}}{3^2} - \frac{28.3^x}{3^2} + 3 = 0\)

\(\frac{3^{2x}}{9} - \frac{28.3^x}{9} + 3 = 0\)

let p = 3\(^x\)

\(\frac{p^{2}}{9} - \frac{{28p}}{9} + 3 = 0\)

multiply through by 9
p\(^2\) - 28p + 27 = 0
p\(^2\) - p - 27p + 27 = 0
p (p - 1) - 27(p - 1) = 0
(p-1)(p-27) = 0
p = 1 or 27
when p = 1
p = 3\(^x\)
3\(^x\) = 1
3\(^x\) = 3\(^0\)
x = 0
when p = 27
3x = 27
3x = 33
x = 3

62.

In how many ways can six persons be paired?

A.

5

B.

10

C.

15

D.

20

Correct answer is C

6C\(_2 = \frac{6!}{[6-2]![2!]}\)

\(\frac{6*5*4!}{4!*2!}\)

= \(\frac{6*5}{2}\)

= 15

63.

If Un = kn\(^2\) + pn, U\(_1\) = -1, U\(_5\) = 15, find the values of k and p.

A.

k = -1, p = 2

B.

k = -1, p = -2

C.

k = 1, p = -2

D.

k = 1, p = 2

Correct answer is C

Un = kn\(^2\) + pn,

U\(_1\) = -1,

U\(_5\) = 15,

when n = 1
U1 = k(1)\(^2\)+ p(1) = -1
k + p = -1 --------eqn1
when n = 5
U\(_5\) = k(5)\(^2\)+ p(5) = 15
25k + 5p = 15 --------eqn2
multiply eqn1 by 5 and eqn2 by 1
5k + 5p = -5 -------eqn3
25k + 5p = 15 -------eqn4
eqn4 - eqn3
20k = 20
k = 1
sub for k in eqn1
1 + p = -1
p = -1 -1 = -2

64.

A particle moving with a velocity of 5m/s accelerates at 2m/s\(^2\). Find the distance it covers in 4 seconds.

A.

16m

B.

26m

C.

36m

D.

46m

Correct answer is C

from the equation of motion

u = 5m/s, a = 2m/s\(^2\), t = 4s 

s = ut + \(\frac{1}{2} at^2\)

s = 5*4 + \(\frac{1}{2} 2*4^2\)

s =  20 + 16

s = 36m

65.

Given that P = {x: x is a multiple of 5}, Q = {x: x is a multiple of 3} and R = {x: x is an odd number} are subsets of μ = {x: 20 ≤ x ≤ 35}, (P⋃Q)∩R.

A.

{20, 21, 25, 30, 33}

B.

{21, 25, 27, 33, 35}

C.

{20, 21, 25, 27, 33, 35}

D.

{21, 25, 27, 30, 33, 35}

Correct answer is B

P = { 20, 25, 30, 35}, Q = {21, 24, 27, 30, 33}, R = {21, 23, 25, 27, 29, 31, 33, 35}


(P⋃Q)∩R = {20, 21, 24, 25, 27, 30, 33, 35} ∩ {21, 23, 25, 27, 29, 31, 33, 35}


= {21, 25, 27, 33, 35}