Further Mathematics Questions and Answers
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
Given that F\(^1\)(x) = x\(^3\)√x, find f(x)
\( \frac{2x^{9/2}}{9} + c \)
\( 2x^{9/2} + c \)
\( \frac{2x^{5/2}}{5} + c \)
\( x^4 + c \)
Correct answer is A
F1 (x) = x\(^3\) √x = x\(^{7/2}\)
F(x) = \(\frac{x^{7/2 +1}}{7/2 + 1}\) + c
= \(\frac{x^{9/2}}{9/2}\)
= \(\frac{2x^{9/2}}{9}\) + c
5.5m
14.5m
26.0m
30.0m
Correct answer is A
From S = 12t + \(\frac{5}{2t^2}\) - t\(^3\);
Distance traveled in 2 seconds
S = 12[2] + \(\frac{5}{2[2]^2}\) - 2\(^3\).
= 24 + 10 - 8 = 26m
Distance traveled in 3 seconds
S = 12[3] + \(\frac{5}{2[3]^2}\) - 3\(^3\)
= 36 + 22.5 - 27 = 31.5m
Distance traveled in the 3rd second
= 31.5m - 26m
: S = 5.5m
418.5m
56.0m
31.5m
30.0m
Correct answer is C
S = 12t + \(\frac{5}{2t^2}\) - t\(^3\);
ds/dt = 12 + 5t - 3t\(^2\)
At max height ds/dt = 0
i.e 12 + 5t - 3t\(^2\)
(3t + 4)(t -3) = 0;
t = -4/3 or 3
Hmax = 12[3] + \(\frac{5}{2[3]^2}\) - 3\(^3\)
= 36 + 45/2 - 27
= 31.5m
In △PQR, \(\overline{PQ}\) = 5i - 2j and \(\overline{QR}\) = 4i + 3j. Find \(\overline{RP}\)
-i - 5j
-9 - j
i + 5j
-9i + j
Correct answer is A
\(\overline{PQ}\) = 5i - 2j; \(\overline{QR}\) = 4i + 3j
\(\overline{RP}\) = \(\overline{PQ}\) - \(\overline{QR}\)
= 5i - 2j - [4i + 3j] = 5i - 2j - 4i - 3j
= i - 5j
5√3
6√2
6√3
9√3
Correct answer is C
No explanation has been provided for this answer.