Further Mathematics questions and answers

Further Mathematics Questions and Answers

Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.

561.

Forces of magnitude 8N and 5N act on a body as shown above. Calculate, correct to 2 dp, the angle that the resultant makes with the horizontal.

A.

80.76°

B.

75.00°

C.

71.99°

D.

15.00°

Correct answer is A

No explanation has been provided for this answer.

562.

Forces of magnitude 8N and 5N act on a body as shown above. Calculate, correct to 2 d.p., the resultant force acting at O.

A.

14.06N

B.

13.00N

C.

9.83N

D.

8.26N

Correct answer is D

No explanation has been provided for this answer.

563.

Forces \(F_{1} = (8N, 030°)\) and \(F_{2} = (10N, 150°)\) act on a particle. Find the horizontal component of the resultant force.

A.

1.7N

B.

4.5N

C.

9.0N

D.

13.0N

Correct answer is A

\(F = F \cos \theta + F \sin \theta\)

where \(F \cos \theta = \text{horizontal component}\)

\(F \sin \theta = \text{vertical component}\)

Horizontal component of resultant = sum of horizontal compoents of individual forces

= \(8 \cos 30 + 10 \cos 150 = 6.928 - 8.66 \approxeq - 1.7N\)

564.

The sum, \(S_{n}\),  of a sequence is given by \(S_{n} = 2n^{2} - 5\). Find the 6th term

A.

112

B.

67

C.

45

D.

22

Correct answer is D

\(S_{n} = 2n^{2} - 5\)

\(T_{n} = S_{n} - S_{n - 1}\)

\(T_{6} = S_{6} - S_{5}\)

= \((2(6^{2} - 5) - (2(5^{2} - 5) = 62 - 40 = 22\)

565.

A 24N force acts on a body such that it changes its velocity from 5m/s to 9m/s in 2 secs.If the body is travelling in a straight line, calculate the distance covered in the period.

A.

22m

B.

18m

C.

14m

D.

10m

Correct answer is C

\(a = \frac{v - u}{t} = \frac{9 - 5}{2} = 2 ms^{-2}\)

\(s = ut + \frac{1}{2}at^{2} = 5(2) + \frac{1}{2}(2 \times 2^{2})\)

= \(14m\)