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Forces F_{1} = (8N, 030°) and \(F_{2} = (10N, 150&de...

Forces F_{1} = (8N, 030°) and F_{2} = (10N, 150°) act on a particle. Find the horizontal component of the resultant force.

A.

1.7N

B.

4.5N

C.

9.0N

D.

13.0N

Correct answer is A

F = F \cos \theta + F \sin \theta

where F \cos \theta = \text{horizontal component}

F \sin \theta = \text{vertical component}

Horizontal component of resultant = sum of horizontal compoents of individual forces

= 8 \cos 30 + 10 \cos 150 = 6.928 - 8.66 \approxeq - 1.7N