1.7N
4.5N
9.0N
13.0N
Correct answer is A
\(F = F \cos \theta + F \sin \theta\)
where \(F \cos \theta = \text{horizontal component}\)
\(F \sin \theta = \text{vertical component}\)
Horizontal component of resultant = sum of horizontal compoents of individual forces
= \(8 \cos 30 + 10 \cos 150 = 6.928 - 8.66 \approxeq - 1.7N\)