Further Mathematics Questions and Answers
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
5n - km = 0
kn + 5m = 0
5n + km = 0
kn - 5m = 0
Correct answer is B
Two lines are parallel if and only if their slopes are equal.
\(kx - 5y + 6 = 0 \implies 5y = kx + 6\)
\(y = \frac{k}{5}x + \frac{6}{5}\)
\(Slope = \frac{k}{5}\)
\(mx + ny - 1 = 0 \implies ny = 1 - mx\)
\(y = \frac{1}{n} - \frac{m}{n}x\)
\(Slope = -\frac{m}{n}\)
\(Parallel \implies \frac{k}{5} = -\frac{m}{n}\)
\(-5m = kn \implies 5m + kn = 0\)
\(\frac{50 \cos \theta}{\sin (\theta + 45)°}\)
\(\frac{50 \cos \theta}{\cos (\theta + 45)°}\)
\(\frac{50 \sin \theta}{\cos (\theta + 45)°}\)
\(\frac{50 \sin \theta}{\sin (\theta + 45)°}\)
Correct answer is D
No explanation has been provided for this answer.
The distance between P(x, 7) and Q(6, 19) is 13 units. Find the values of x.
1 or -7
1 or 7
1 or 11
5 or -5
Correct answer is C
\(d = \sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2}}\)
\(13 = \sqrt{(x - 6)^{2} + (7 - 19)^{2}}\)
\(13^{2} = x^{2} - 12x + 36 + 144\)
\(169 = x^{2} - 12x + 180\)
\(x^{2} - 12x + 180 - 169 = 0 \implies x^{2} - 12x + 11 = 0\)
\((x - 1)(x - 11) = 0 \implies x = \text{1 or 11}\)
-4
-3
0
6
Correct answer is D
\(y = x^{2} - 6x + 11\)
\( y = a(x - h)^{2} + k\)
\(a(x - h)^{2} + k = a(x^{2} - 2hx + h^{2}) + k\)
\(ax^{2} - 2ahx + ah^{2} + k = x^{2} - 6x + 11\)
Comparing, we have
\(a = 1\)
\(2ah = 6 \implies 2h = 6; h = 3\)
\(ah^{2} + k = 11 \implies (1 \times 3^{2}) + k = 11\)
\(9 + k = 11 \implies k = 2\)
\(\therefore a + h + k = 1 + 3 + 2 = 6\)
25
15
\(3\sqrt{7}\)
\(\sqrt{10}\)
Correct answer is A
Change in momentum = m (v - u)
= \(5 \times (\begin{pmatrix} 4 \\ 7 \end{pmatrix} - \begin{pmatrix} 1 \\ 3 \end{pmatrix})\)
= \(5 \times \begin{pmatrix} 3 \\ 4 \end{pmatrix}\)
= \(\begin{pmatrix} 15 \\ 20 \end{pmatrix}\)
\(|m(v - u)| = \sqrt{15^{2} + 20^{2}} = \sqrt{625} = 25\)