The distance between P(x, 7) and Q(6, 19) is 13 units. Fi...
The distance between P(x, 7) and Q(6, 19) is 13 units. Find the values of x.
1 or -7
1 or 7
1 or 11
5 or -5
Correct answer is C
d=√(x1−x2)2+(y1−y2)2
13=√(x−6)2+(7−19)2
132=x2−12x+36+144
169=x2−12x+180
x2−12x+180−169=0⟹x2−12x+11=0
(x−1)(x−11)=0⟹x=1 or 11
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