Further Mathematics Questions and Answers
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
-4
0
4
12
Correct answer is D
\(Gradient = \frac{y_{1} - y_{2}}{x_{1} - x_{2}} \)
\(\frac{1}{2} = \frac{5 - 9}{4 - x}\)
\(\frac{1}{2} = \frac{-4}{4 - x} \implies -8 = 4 - x\)
\(x = 4 + 8 = 12\)
12
11
\(\frac{11}{2}\)
\(\frac{9}{2}\)
Correct answer is C
\(f(x) = 2x - 1; g(x) = x^{2} + 1\)
\(f(x) = 2x - 1\)
\(f(y) = 2y - 1 \)
\(x = 2y - 1 \implies 2y = x + 1\)
\(y = \frac{x + 1}{2}\)
\(g(3) = 3^{2} + 1 = 10\)
\(f^{-1}(10) = \frac{10 + 1}{2} = \frac{11}{2}\)
130
192
210
260
Correct answer is B
\(S_{n} = \frac{n}{2}(2a + (n - 1)d)\) ( for an arithmetic progression)
\(S_{3} = 18 = \frac{3}{2}(2(4) + (3 - 1) d) \)
\(18 = \frac{3}{2} (8 + 2d)\)
\(18 = 12 + 3d \implies 3d = 6\)
\(d = 2\)
\(\therefore T_{1} = 4 \implies T_{2} = 4 + 2 = 6; T_{3} = 6 + 2 = 8\)
Their product = \(4 \times 6 \times 8 = 192\)
Which of the following is the same as \(\sin (270 + x)°\)?
\(\sin x\)
\(\tan x\)
\(- \sin x \)
\(- \cos x\)
Correct answer is D
No explanation has been provided for this answer.
\(x^{2} - 3x + 2 = 0\)
\(x^{2} - 2x + 3 = 0\)
\(x^{2} - 3x - 2 = 0\)
\(x^{2} - 2x - 3 = 0\)
Correct answer is A
Given \(ax^{2} + bx + c = 0 (\text{general form of a quadratic equation})\)
We have \(x^{2} + \frac{b}{a}x + \frac{c}{a} = 0\)
\( x^{2} - (-\frac{b}{a})x + \frac{c}{a} = 0\)
\(\implies x^{2} - (\alpha + \beta)x + (\alpha \beta) = 0\)
\(\therefore \text{The equation is} x^{2} - 3x + 2 = 0\)