A bag contains 8 red, 4 blue and 2 green identical balls....
A bag contains 8 red, 4 blue and 2 green identical balls. Two balls are drawn randomly from the bag without replacement. Find the probability that the balls drawn are red and blue.
A. 12/91 B. C. D.
12/91
16/91
30/91
32/91
Correct answer is D
Total balls = 8+4+2= 14
n(R) = 8, n (B) =4, n(G) = 2
Without replacement, it is p(RB) or p(BR)
= (8/14 x 4/13) + (4/14 + 8/13) = 16/91 + 16/91
= 32/91
Two statements are represented by p and q as follows: p : He is brilliant; q : He is regular in c...
The table shows the distribution of marks obtained by some students in a test Marks 0-9 10-...
Given that p=4i+3j, find the unit vector in the direction of p....
Which of the following is the semi-interquartile range of a distribution? ...
The roots of the quadratic equation 2x2−5x+m=0 are α and β, where m is...
The sales of five salesgirls on a certain day are as follows; GH¢ 26.00, GH¢ 39....
Two functions f and g are defined on the set of real numbers by f:x→x2+1 and \(g : x ...