y+x-3 =0
y-x+6=0
y - x - 6=0
y -x+ 3 =0
Correct answer is C
From y= 2x- 5x 10 ; dy/dx= 4x-5
But at (1, 7); m1 = (dy/dx)1,7
= 4(1) - 5 = -1
Using m1m2,= -1; m2 = 1.
Gradient m2, of normal at (1,7) is 1.
Using y - y1 = m(x - x1)
y - 7 = 1(x - 1) ;
y - 7 = x - 1
y - x - 6 = 0
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