y+x-3 =0
y-x+6=0
y - x - 6=0
y -x+ 3 =0
Correct answer is C
From y= 2x- 5x 10 ; dy/dx= 4x-5
But at (1, 7); m\(_1\) = (dy/dx)\(_{1,7}\)
= 4(1) - 5 = -1
Using m\(_1\)m\(_2\),= -1; m\(_2\) = 1.
Gradient m\(_2\), of normal at (1,7) is 1.
Using y - y\(_1\) = m(x - x\(_1\))
y - 7 = 1(x - 1) ;
y - 7 = x - 1
y - x - 6 = 0
In how many ways can 3 prefects be chosen out of 8 prefects? ...
Find \(\lim \limits_{x \to 3} \frac{x + 3}{x^{2} - x - 12}\)...
Which of the following is a factor of the polynomial \(6x^{4} + 2x^{3} + 15x + 5\)?...
Simplify \(\frac{^{n}P_{3}}{^{n}C_{2}} + ^{n}P_{0}\)...
Given that \(f(x) = 2x^{2} - 3\) and \(g(x) = x + 1\) where \(x \in R\). Find g o f(x)....
Simplify \(\frac{1 + \sqrt{8}}{3 - \sqrt{2}}\)...
If \(f(x) = \frac{1}{2 - x}, x \neq 2\), find \(f^{-1}(-\frac{1}{2})\)....