−x1−x,x≠1
11−x,x≠1
−11−x,x≠1
x1−x,x≠1
Correct answer is A
x∗y=x+y−xy
Let x−1 be the inverse of x, so that
x∗x−1=x+x−1−x(x−1)=0
x+x−1−x(x−1)=0⟹x(x−1)−x−1=x
x−1(x−1)=x⟹x−1=xx−1
= x−(1−x)=−x1−x,x≠1
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