JAMB Mathematics Past Questions & Answers - Page 110

546.

From the figure above, what is the value of p?

A.

135o

B.

90o

C.

60o

D.

45o

Correct answer is B

In the figure above, qo = 30o (vertically opposite angles)

(P + 2q)o + 30o = 180o(angles on a straight line)

p + 2 x 30o + 30o = 180o

p + 60o + 30o = 180o

p + 90o = 180o

p = 180o - 90o

= 90o

547.

In the figure above, KL//NM, LN bisects < KNM. If angles KLN is 54o and angle MKN is 35o, calculate the size of angle KMN.

A.

91o

B.

89o

C.

37o

D.

19o

Correct answer is C

In the diagram above, \(\alpha\) = 54o(alternate angles; KL||MN) < KNM = 2\(\alpha\) (LN is bisector of < KNM) = 108o

35o + < KMN + 108o = 180o(sum of angles of \(\bigtriangleup\))

< KMN + 143o = 180o

< KMN = 180o - 143o

= 37o

548.

From the venn diagram above, the shaded parts represent

A.

(P\(\cap\)Q)\(\cup\)(P\(\cap\)R)

B.

(P\(\cup\)Q)\(\cap\)(P\(\cap\)R)

C.

(P\(\cup\)Q)\(\cup\)(P\(\cup\)R)

D.

(P\(\cap\)Q)\(\cup\)(P\(\cup\)R)

Correct answer is A

No explanation has been provided for this answer.

549.

The pie chart above shows the statistical distribution of 80 students in five subjects in an examination. Calculate how many student offer Mathematics.

A.

30

B.

11

C.

50

D.

20

Correct answer is B

5x° + (16x - 24)° + 5x° + (4x + 12)° + (6x + 12)° = 360°

36x° - 24 + 12 + 12 = 360°

36x° = 360°

x° = \(\frac{360°}{36}\)

= 10°

Thus, the angle of sector representing Mathematics is 5 x 10° = 50°. Hence the number of students who offer mathematics is

\(\frac{50}{360} \times 80 \approx 11\)