From the figure above, what is the value of p?
135o
90o
60o
45o
Correct answer is B
In the figure above, qo = 30o (vertically opposite angles)
(P + 2q)o + 30o = 180o(angles on a straight line)
p + 2 x 30o + 30o = 180o
p + 60o + 30o = 180o
p + 90o = 180o
p = 180o - 90o
= 90o
91o
89o
37o
19o
Correct answer is C
In the diagram above, \(\alpha\) = 54o(alternate angles; KL||MN) < KNM = 2\(\alpha\) (LN is bisector of < KNM) = 108o
35o + < KMN + 108o = 180o(sum of angles of \(\bigtriangleup\))
< KMN + 143o = 180o
< KMN = 180o - 143o
= 37o
From the venn diagram above, the shaded parts represent
(P\(\cap\)Q)\(\cup\)(P\(\cap\)R)
(P\(\cup\)Q)\(\cap\)(P\(\cap\)R)
(P\(\cup\)Q)\(\cup\)(P\(\cup\)R)
(P\(\cap\)Q)\(\cup\)(P\(\cup\)R)
Correct answer is A
No explanation has been provided for this answer.
30
11
50
20
Correct answer is B
5x° + (16x - 24)° + 5x° + (4x + 12)° + (6x + 12)° = 360°
36x° - 24 + 12 + 12 = 360°
36x° = 360°
x° = \(\frac{360°}{36}\)
= 10°
Thus, the angle of sector representing Mathematics is 5 x 10° = 50°. Hence the number of students who offer mathematics is
\(\frac{50}{360} \times 80 \approx 11\)
460mins
720mins
960mins
200mins
Correct answer is B
80 + 160 + 200 + 80 + 128 + 72 = 720minutes