\(\frac{81}{32}\)
\(\frac{9}{8}\)
\(\frac{1}{4}\)
\(\frac{32}{729}\)
Correct answer is D
ar = \(\frac{2}{9}\) .....(i)
ar\(^3\) = \(\frac{8}{81}\) ......(ii)
\(\frac{ar3}{ar} = \frac{8}{81} \times \frac{9}{2}\)
r\(^2 = \frac{4}{9}\)
r = \(\sqrt{\frac{4}{9}}\)
= \(\frac{2}{3}\)
ar = \(\frac{2}{9}\)
a(\(\frac{2}{3}\)) = \(\frac{2}{9}\)
a = (\(\frac{2}{3}\)) = \(\frac{2}{9}\)
a = \(\frac{2}{9} \times \frac{3}{2}\)
a = \(\frac{1}{3}\)
T\(_r\) = ar\(^5\) = (\(\frac{1}{3}\))(\(\frac{2}{5}\))\(^5\)
= \(\frac{32}{729}\)
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