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Find the stationary point of the curve \(y = 3x^{2} - 2x^{3}...

Find the stationary point of the curve y=3x22x3.

A.

(1, 0)

B.

(-1, 0)

C.

(1, 1)

D.

(-1, -1)

Correct answer is A

y=3x22x3

dydx=6x6x2=06x(1x)=0

x=0,1, when x = 1, y = 0.

when x = 1, y = 0.

The stationary point is (1, 0)