Eight football clubs are to play in a league on home and away basis. How many matches are possible?
14
28
56
128
Correct answer is C
Number of matches possible = \(2 \times ^{8}C_{2}\) (Home and away repitition of the matches)
= \(2 \times \frac{8!}{(8 - 2)! 2!}\)
= \(2 \times 28\)
= 56