√25
5√2
2√5
5√22
Correct answer is A
F=F1+F2
(2i−5j)+(−3i+4j)=(−i−j)
F=ma⟹(−1,−1)=5a
a=(−15,−15)
|a|=√(−15)2+(−15)2=√225
|a|=√25ms−2
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