(−1415)ms−1
(−21)ms−1
(4−9)ms−1
(14−9)ms−1
Correct answer is C
u=(−53)ms−1
a=(3−4)ms−2;t=3secs
v=u+at⟹v=(−53)+(3−4)×3
= (−53)+(9−12)=(4−9)ms−1\)
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