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Find the coefficient of x3 in the expansion of \([\fr...

Find the coefficient of x3 in the expansion of [13(2+x)]6

A.

135729

B.

149729

C.

152729

D.

160729

Correct answer is D

[13(2+x)]6=(23+x3)6

The coefficient of x3 is 

6C3(23)3(13)3x3=(6!3!3!)(827)(127)x3

= 160729