\(-\log_{3} 4\)
\(-\log_{3} 2\)
\(3\log_{3} 2\)
\(3\log_{3} 4\)
Correct answer is C
\(2\log_{3} 8 - 3\log_{3} 2 = \log_{3} 8^{2} - \log_{3} 2^{3}\)
= \(\log_{3}(\frac{64}{8}) \)
= \(\log_{3} 8 = \log_{3} 2^{3}\)
= \(3 \log_{3} 2\)
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