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Find the coordinates of the centre of the circle \(4x^{2} + ...

Find the coordinates of the centre of the circle 4x2+4y25x+3y2=0.

A.

(54,34)

B.

(38,58)

C.

(58,38)

D.

(54,34)

Correct answer is C

Equation : (xa)2+(yb)2=r2

Expanding : x2+y22ax2by+a2+b2=r2

Given, 4x2+4y25x+3y2=0

Divide through by 4 to make the coefficient of x2 and y2 to be 1.

x2+y254x+34y12=0

Comparing, 2a=54a=58

2b=34b=38

(a,b)=(58,58)