\(\frac{560}{243}\)
\(\frac{841}{243}\)
\(\frac{1120}{243}\)
\(\frac{4481}{243}\)
Correct answer is C
\(^{10}C_{7 - 1} (2^{10 - 6}) (\frac{-1}{3})^{6}\)
\(\frac{10!}{(10 - 6)! 6!} \times 16 \times \frac{1}{243} \)
= \(210 \times 16 \times \frac{1}{729} \)
= \(\frac{1120}{243}\)