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The mean and median of integers x, y, z and t are 5 and z...

The mean and median of integers x, y, z and t are 5 and z respectively. If x < y < z < t and y = 4, find (x + t).

A.

12

B.

11

C.

10

D.

8

Correct answer is A

Mean:x+4+z+t4=5x+4+z+t=20

x+z+t=16...(1)

Median:4+z2=z4+z=2z

4=z

From 1, 

x+4+t=16

x+t=12