The mean and median of integers x, y, z and t are 5 and z...
The mean and median of integers x, y, z and t are 5 and z respectively. If x < y < z < t and y = 4, find (x + t).
12
11
10
8
Correct answer is A
Mean:x+4+z+t4=5⟹x+4+z+t=20
⟹x+z+t=16...(1)
Median:4+z2=z⟹4+z=2z
4=z
From 1,
⟹x+4+t=16
x+t=12
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