1
√3
√11
√6
Correct answer is B
The equation of a circle is given as (x−a)2+(y−b)2=r2
Expanding this, we have x2+y2−2ax−2by+a2+b2=r2
Comparing with the given equation, 3x2+3y2+6x−12y+6=0≡x2+y2+2x−4y+2=0 (making the coefficients of x2 and y2 = 1 , we get that
−2a=2⟹a=−1
2b=4⟹b=2
r2−a2−b2=−2
∴
r = \sqrt{3}
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