x2+y2−5x+3=0
x2+y2−2x−6y−13=0
x2+y2−x+5y−6=0
x2+y2−x−y−8=0
Correct answer is D
Given the endpoints of the diameter |EF|, the midpoint is the centre of the circle
= (−2+32,−1+22)=(12,12)
The radius is the distance from the centre to any point on the circle. Using (12,12) and (3,2);
r2=(3−12)2+(2−12)2=254+94
r2=344
The equation of a circle is given as:
(x−a)2+(y−b)2=r2, (a, b) as the centre of the circle.
=(x−12)2+(y−12)2=344
x2−x+14+y2−y+14=172
= x2−y2−x−y−8=0
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