f−1:x→1+2x2−x,x≠2
f−1:x→1−2xx+2,x≠−2
f−1:x→1−2xx−2,x≠2
f−1:x→1+2xx+2,x≠−2
Correct answer is A
f(x)=2x−1x+2
y=2x−1x+2
x=2y−1y+2⟹x(y+2)=2y−1
xy−2y=−1−2x⟹y=−1−2xx−2
f−1:x→1+2x2−x;x≠2
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