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Find the equation of the straight line that passes throug...

Find the equation of the straight line that passes through (2, -3) and perpendicular to the line 3x - 2y + 4 = 0.

A.

2y - 3x = 0

B.

3y - 2x + 5 = 0

C.

3y + 2x + 5 = 0

D.

2y - 3x - 5 = 0

Correct answer is C

Given line: 3x2y+4=02y=3x+4

y=32x+2

Gradient(dydx)=32

Gradient of perpendicular line = 132=23

y(3)x2=23

y+3x2=23

3(y+3)=2(x2)3y+2x+94=0

= 3y+2x+5=0