Solve 6 sin 2θ tan θ = 4, where 0º ...
Solve 6 sin 2θ tan θ = 4, where 0º < θ < 90º
18.43º
30.00º
35.26º
19.47º
Correct answer is C
6 sin 2θ tan θ = 4, where 0º < θ < 90º
sin 2θ = 2sin θ cos θ and tanθ = \frac{sinθ}{cosθ}
= 6 x 2sin θ cos θ x \frac{sin θ}{cos θ} = 4
= sin^2 θ = 4
= sin^2 θ = \frac{4}{12}=\frac{1}{3}
=sin θ = \frac{\sqrt1}{3}=\frac{1}{\sqrt3}
= θ = sin^{-1}(\frac{1}{\sqrt3})
∴ θ = 35.26º
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