\(\frac{-32}{7}\)
\(\frac{-23}{7}\)
\(\frac{23}{7}\)
\(\frac{32}{7}\)
Correct answer is C
\(\frac{15 - 2x}{(x+4)(x-3)}\) = \(\frac{R}{(x+4)}\) + \(\frac{9}{7(x-3)}\)
15-2x = R(x - 3) +9(x +4)/7
Put x =-4, we have 15 -2(-4) = -7R
23 -7R;
R = 23/7
A particle starts from rest and moves in a straight line such that its velocity, V ms\(^{-1}\),...
Given that \(a^{\frac{5}{6}} \times a^{\frac{-1}{n}} = 1\), solve for n...
Integrate \((x - \frac{1}{x})^{2}\) with respect to x....
If P(x - 3) + Q(x + 1) = 2x + 3, find the value of (P + Q). ...
Simplify: \((1 - \sin \theta)(1 + \sin \theta)\)...
Two forces \(F_{1} = (10N, 020°)\) and \(F_{2} = (7N, 200°)\) act on a particle. Find the re...
Find the derivative of \(\sqrt[3]{(3x^{3} + 1}\) with respect to x....