18.75 N
15.75 N
9.50 N
8.66 N
Correct answer is D
F_{1} = (5 N, 060°) = 5 \cos 60 i + 5 \sin 60 j = 2.5 i + \frac{5\sqrt{3}}{2}j
F_{2} = (10 N, 180°) = 10 \cos 180 i + 10 \sin 180 j = -10i
R = F_{1} + F_{2} = -7.5 i + \frac{5\sqrt{3}}{2}j
|R| = \sqrt{(-7.5)^{2} + (\frac{5\sqrt{3}}{2})^{2}}
= \sqrt{56.25 + 18.75} = \sqrt{75}
= 8.66 N
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