13(x−1x)3+c
x33−x√1x3+c
x33−2x+1x3+c
x33−2x−1x+c
Correct answer is D
(x−1x)2=x2−2+1x2
∫(x2+1x2−2)dx
= ∫(x2+x−2−2)dx
= x33−2x−1x
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