1√29(2i+5j)
1√29(−2i+5j)
129(2i−5j)
129(−2i−5j)
Correct answer is B
The unit vector, ˆn is given by ˆn=→r|→r|
= (−2i+5j)√(−2)2+52=(−2i+5j)√29
= 1√29(−2i+5j)
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