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If \sin x = -\sin 70°, 0° < x < 360°, ...

If \sin x = -\sin 70°, 0° < x < 360°, determine the two possible values of x.

A.

110°, 250°

B.

110°, 290°

C.

200°, 250°

D.

250°, 290°

Correct answer is D

The value of the sine of an angle is negative in the third and fourth quadrant. Hence options A and B are not the options.

\sin 250 = -\sin (250 - 180) = - \sin 70

\sin 290 = - \sin (360 - 290) = - \sin 70