A body of mass 10kg moving with a velocity of 5\(ms^{-1}\) collides with another body of mass 15kg moving in the same direction as the first with a velocity of 2\(ms^{-1}\). After collision, the two bodies move together with a common velocity v\(ms^{-1}\).

3.2

5.3

7.0

8.0

Correct answer is A

Momentum of bodies with common velocity = \(m_{1}v_{1} + m_{2}v_{2} = (m_{1} + m_{2})v\)

\((10 \times 5) + (15 \times 2) = (10 + 15)v\)

\(50 + 30 = 25v \implies v = \frac{80}{25} = 3.2ms^{-1}\)

See all Further Mathematics questions & answers

See more WAEC questions & answers