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Given that sinx=32 and \(\cos x >...

Given that sinx=32 and cosx>0, find x

A.

300°

B.

240°

C.

120°

D.

60°

Correct answer is A

In order to do this, simply find the option in the range where only the cos is +ve. This occurs in the range 270° \leq x \leq 360°.

Check: \sin 300 = - \sin 60 = \frac{-\sqrt{3}}{2}

\cos 300 = \cos 60 = \frac{1}{2}