\(2\sqrt{2}\)
\(3\sqrt{2}\)
3
4
Correct answer is D
\(\sqrt{128} = \sqrt{64\times2} = 8\sqrt{2}\)
\(\sqrt{32} = \sqrt{16\times2} = 4\sqrt{2}\)
Simplifying, we have \(\frac{8\sqrt{2}}{4\sqrt{2} - 2\sqrt{2}} = \frac{8\sqrt{2}}{2\sqrt{2}}\)
= 4
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