The third of geometric progression (G.P) is 10 and the si...
The third of geometric progression (G.P) is 10 and the sixth term is 80. Find the common ratio.
2
3
4
8
Correct answer is A
Tn=arn−1 ( Geometric Progression)
T3=ar3−1=ar2=10....(1)
T6=ar6−1=ar5=80.....(2)
Divide (2) by (1)
r5−2=r3=8
r=3√8=2
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