Forces 50N and 80N act on a body as shown in the diagram. Find, correct to the nearest whole number, the horizontal component of the resultant force.
A.
13N
B.
43N
C.
57N
D.
95N
Correct answer is A
Given a force F, the horizontal component = \(F\cos \theta\)
R = \(-50\cos 30 + 80\cos 45\)
= \(-50(\frac{\sqrt{3}}{2}) + 80(\frac{\sqrt{2}}{2})\)
= \( -25\sqrt{3} + 40\sqrt{2} = -43.30 + 56.67 \)
= \(13.37N \approxeq 13N\)