Further Mathematics Questions and Answers
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
A polynomial is defined by f(x+1)=x3+px2−4x+2, find f(2)
-8
-2
2
8
Correct answer is C
Given: f(x+1)=x3+3x2−4x+2.
f(2)=f(x+1)⟹x+1=2;x=1
f(2)=13+3(1)2−4(1)+2=1+3−4+2=2
If (x + 1) is a factor of the polynomial x3+px2+x+6. Find the value of p.
-8
-4
4
8
Correct answer is B
If (x + 1) is a factor, then f(-1) = 0.
(−1)3+p(−1)2+(−1)+6=0
−1+p−1+6=0⟹p+4=0
p=−4
QRS is a triangle such that →QR=(3i+2j) and →SR=(−5i+3j), find →SQ.
8i + j
2i - j
-2i - 3j
-8i - j
Correct answer is A
→SQ=→SR+→RQ
→RQ=−→QR=−(3i+2j)=−3i−2j
→SQ=(−5i+3j)−3i−2j=−8i+j
Evaluate log10(13+14)+2log102+log10(37)
-3
0
56
1
Correct answer is B
log10(13+14)+2log102+log10(37)
13+14=712
= log10(712×22×37)
= log101=0
Given that sinx=−√32 and cosx>0, find x
300°
240°
120°
60°
Correct answer is A
In order to do this, simply find the option in the range where only the cos is +ve. This occurs in the range 270° \leq x \leq 360°.
Check: \sin 300 = - \sin 60 = \frac{-\sqrt{3}}{2}
\cos 300 = \cos 60 = \frac{1}{2}