\(4 ms^{-2}\)
\(6 ms^{-2}\)
\(8 ms^{-2}\)
\(10 ms^{-2}\)
Correct answer is D
\(v(t) = (3t^{2} - 2t) ms^{-1}\)
\(a(t) = \frac{\mathrm d v}{\mathrm d t} = (6t - 2) ms^{-2}\)
\(a(2) = 6(2) - 2 = 12 - 2 = 10 ms^{-2}\)
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